1. . In a workshop there are 4 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
B.16
C.80
D.48
E.56
A. 140
B. 160
C. 124
D.134
E. 143
A. 2
B. 4
C. 6
D. 8
E. 10
A. 648
B. 504
C.576
D. 810
E. 672
A. 41
B. 46
C.36
D.66
E. 56
A. 27
B. 36
C. 72
D. 112
E. 422
A. 2/5
B. 3/5
C. 3/10
D. 3/4
E. 2/3
A. 8/125
B.1/30
C. 2/5
D.1/720
E. 3/10
A.1/XY
B. X/Y
C. Y/X
D. 1/(X+Y)
E. 1/(X-Y)
A. 1
B.1/2
C. 3/4
D. 1/4
E. 1/3
ANS: You must multiply your options to every item. (2 shelves) x (4 beds) x (3 closets + 7 chairs) = 80 possibilities.
ANS: You must multiply your options to every item. (7 chairs) x (4 beds) x (3 closets + 2 shelves) = 140 possibilities.
ANSTreat the two who must sit together as one person. You have two possible sitting arrangements. Then remember that the two that sit together can switch places. So you have two times two arrangements and a total of four
ANS: For the first digit you have 9 options (from 1 to 9 with out 0), for the second number you have 9 options as well (0 to 9 minus the first digit that was already used) and for the third digit you have 8 options left. So the number of possibilities is 9 x 9 x 8 = 648.
ANS: There are (8 x 9) 72 possibilities of shirts + pants. (2 x 3) 6 Of the combinations are not allowed. Therefore, only (72 – 6) 66 combinations are possible.
ANS: First digit is 1, the second is 2, the third can be (7,8,9), the forth can be (3,6,9), the fifth and the sixth are dependent with one another. The fifth one is 3 times bigger than the sixth one, therefore there are only 3 options there: (1,3), (2,6), (3,9). All together there are: 1 x 1 x 3 x 3 x 3 = 27 options.
ANS:The probability of picking the first jar is ½, the probability of picking up a white ball out of jar A Is 3/(3+2) = 3/5. The probability of both events is 1/2 x 3/5 = 3/10
ANS: The probability for the first one to be black is: 4/(4+6) = 2/5. The probability for the second one to be black is: 3/(3+6) = 1/3. The probability for the third one to be black is: 2/(2+6) = 1/4. The probability for all three events is (2/5) x (1/3) x (1/4) = 1/30.
ANS: Let Z be the probability of breaking the jar, therefore the probability of both events happening is Z x (1/X) = (1/Y). Z = X/Y.
ANS: The probability of the coin is independent on its previous outcomes and therefore the probability for “head” or “tail” is always ½.