A. 25
B. 30
C.40
D. 60
E. 64
A. 12
B. 16
C. 18
D. 20
E. 24
A. 4
B. 6
C. 8
D.10
E. 12
A. 4/5
B. 5/7
C. 5/4
D. 12/7
E. 4/3
F. 8/9
G. 9/8
A. 6
B. 7.5
C. 8
D. 9
E. 10.5
A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 1/6
F. 1/7
G. 1/8
A. 2/15
B. 4/15
C. 7/15
D. 8/15
E. 11/15
A. 7hr 30min
B. 7hr 45min
C. 8hr
D. 8hr 15min
E. 8hr 30min
A.3
B. 4
C.5
D. 6
E. 7
F. 8/15
G. 9/17
A.12
B. 13
C.14
D. 15
E. 16
A. 1:2
B. 2:1
C. 3:2
D. 2:3
E. 4:5
A. 2:1
B. 2:3
C. 3:4
D. 4:3
E. 3:2
A. 3
B. 4
C. 5
D. 6
E. 8
A. 3
B. 5
C.7
D.9
E. 10
A. 3
B. 5
C. 6
D. 8
E. 9
Column A | Column B |
Efficiency of 3 children | Efficiency of 2 adults |
A. Column A is greater
B. Column B is greater
C. Both are equal
D. Data is insufficient to compare
A. 10
B. 12
C. 15
D. 16
E. 18
A. 100
B. 125
C. 150
D. 200
E. 225
Explanatory Answer
Let us assume that Jose will take x days to complete the task if he works alone and that Jane will take y days to complete the task if she worked alone.
From the information provided in the first statement of the question, we know that they will complete the task in 20 days, if they worked together on the task.
Therefore,1/x + 1/y = 1/20
From the second statement, we can conclude that x/2 + y/2 = 45
Or, x + y = 90 => x = 90 - y.
Substituting the value of x as 90 - y in the first equation, we get 1/(90-x) + 1/y = 1/20
Or y2 - 90 + 1800 = 0.
Factorizing and solving for y, we get y = 60 or y = 30.
If y = 60, then x = 90 - y = 90 - 60 = 30 and
If y = 30, then x = 90 - y = 90 - 30 = 60.
As the question clearly states that Jane is more efficient than Jose, the second answer is the only possible alternative.
Hence, Jose will take 60 days to complete the task if he worked alone and Jane will take only 30 days to complete the same task.
. Similarly, B will complete 1/30th of the project in a day.
Let the total number of days taken to complete the project be x days.
Then, B would have worked for all x days, while A would have worked for (x - 10) days.
Therefore, A would have completed (x-10)/20th of the project and B would have complete x/30 th of the project.
i.e., (x-10)/20 + x/30 = 1
Solving for x, we get x = 18.
Explanatory Answer: Ram takes 24 days to complete the work, if he works alone.
As Krish is twice as efficient as Ram is, Krish will take half the time to complete the work when Krish works alone, i.e., in 12 days.
Ram completes 1/24 th of the work in a day.
Krish completes 1/12 th of the work in a day.
When they work together, they will complete 1/24 + 1/12 = 1/8 th work in a day.
Therefore, when they work together they will complete the work in 8 days.
One woman and one man can build a wall together in two hours,
One woman and two girls can build a wall together in two hours
from the above two we can say that: efficiency of one man = Efficiency of two girls.
given that one man and one girl can do a work in four hours.
it means 3 girls can finish the work in 4 hrs. i.e 1 girl can finish the workin 12hrs.
1 man can finish the work in 6 hrs.
1 women can finish the work in 3 hrs.Assume total work be 12 units. 1 girl will do one unit per hour. 1 man will do 2 units per hour. 1 women will do 4 units per hour.
Therefore,work will be finished in 12/7 hours
3(A+B) requires 1 hour to produce 1 widget.
2A+B requires 2hrs to produce 1 widget.
2(2A+B) requires 1hr to produce 1 widget
therefore 3(A+B)= 4A+2B
A=B,i.e efficiency of A and B are same. A can finish 1 widget in 6hrs.
Answer:7.5
Solution:
Assume "A" does 10 units per day. then total work is 10X12= 120 unit
As "B" is 60% more efficient "B" does 16 units per day.
To complete 120 units of work "B" requires 120/16 days= 7.5.
Solution:Assume total work be 60 units(lcm of 15 and 20).
Adam will do 60 units in 15 days.
Therefore he will do 4 units per day.
Eve can do 60 units in 20 days
Therefore Eve does 3 units per day.
together they can do 7 unts per day
in four days they finish 4x7=28 units
Leftover work is (60-28)=32units.
Fraction of work left over is 32/60=8/15.
Solution:Ram will type 32/6 pages in 1hr.
Shaam will type 40/5 pages in 1hr
Together they will type (32/6+40/5) pages in 1 hr.
There dore to type 110 pages they will take 110/(32/6+40/5)hr=8hr 15min.
Answer is 7.
Solution:
7 men take 12 days to complete a job
But 7 days two men left.
If there were 7 members they can finsish the remaing work in 5 days
Therefore 5 members can finish the work in 7 days (m1d1=m2d2)
Answer – 120
Solution:A can do 1/4 of the job in 3 days
it means A can finish the work in 12 days.
B can do 1/6 of the same job in 4 days
it means B can finish the work in 24 days
Therefore A is twice as efficient as B.
The amount will be shared in the ratio 2:1.
A's share =(2/3)of 180=120.
Answer:
SOLUTION: Let us assume total work be 60 uinits (lcm of 20, 30, 60).
A can do 60 units of work in 20 days.
A can do 3units/day.
B can do 60 units of work in 30 days
B can do 2units/day.
C can do 60 units of work in 60 days
C can do 1unit/day.
A,B and C together will do (3+2+1) units/day. i.e 6 units/day.
A works for two days and on third day all three together will work.
In three days the work done will be (3+3+6)=12units/cycle.
1 cycle = 3 days
To do 60 units of work the time taken will be (60 units)/( 12units/cycle ) = 5 cycles = 5 X 3days= 15 days.
Explanatory Answer
Efficiency of (5m+2b)= 4 times the efficiency of ( 1m+1b)
Efficiency of (5m+2b)= efficiency of ( 4m+4b)
Efficiency of 1m= efficiency of 2b
Efficiency of 1m= 2 times efficiency of 1b
(Efficiency of 1m/ efficiency of 1b)=2/1.
Explanatory Answer
5 (12m+16b)= 4(13m+24b)
on simplification m/b=2/1.
Explanatory Answer
efficiency of 16X12men= Efficiency of 24X18 children
efficiency ratio of men to children is (24X18)/(16X12)= 9/4.
4 men = 9 children=> 12men=27 children.
12 men + 8 children= 35 children.
Assume each children will do 1 unit per day, then total work=24x18.
Twelve men and eight children worked for eight days= 35 X 8
After 8 days work left = 24X18-35X8=152
As 3 more children joined the group the no. of children will be 38.
152/38=4 days
Explanatory Answer
10 women can complete a work in 7 days
10 children take 14 days to complete the work.
i.e from the above two we can say that two children can be replaced by 1 women.
5 women and 10 children efficiency is same as 10 women.
There for the answer is 7 days.
Efficiency of 16X12 children = Efficiency of 8X12 adults
efficiency ratio of adult to children=2/1.
Assume each children will do one unit per day.
Total work =16X12=192.
16 adults can be replaced with 32 children.
In three days the work done=32X3=96.
Total no. of children after three days(10 adults left and 4 children joined)=16.
Remaining (192-96=96) units of work done in 96/16=6days.
Column A | Column B |
Efficiency of 3 children | Efficiency of 2 adults |
Solution:Efficiency of 16X12 children = Efficency of 12X 8 adults.
Efficiency ratio of adult to children=2/1.
From this we can say that efficency of 2 adults is greater than the efficiency of 3 children.
Column B is greater.
Solution:12 men can complete 100% of work in 4 days.
6 men can complete 25% of work in two days
15 women can complete 100% of work in 4 days
It means in one day 15 women can do 25% of the work.
Threfore in three days 15 women can complete 75% of the work.
The Answer is 15.
Solution:A can earn $1500 if he alone works for 10 days.
Per day A will get $150
B can earn $1500 if he alone works for 15 days.
Per day B will get $100
For the five days of work A & B together will get 5(150+100)= $1250
The remaining amount($250) will go to C for two days of work
Per day C will get $125
Daily B and C will get (100+125)= $225.