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1. 4/5 Of a number exceeds it’s 2/3 by 8. The number is
2.The sum of two numbers is 29 and the difference of their squares is 145. The difference between the number is
3. The sum of two numbers is twice their difference. If one of the numbers is 10, the other number is?
4. The product of two numbers is 120. The sum of their squares is 289. The sum of the two numbers is:
5. If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, it becomes 3/4 ; the fraction is :?
Explanation for Question 1
4/5 Of a number exceeds it’s 2/3 by 8. The number is
Assume the original number be 15X
4/5 of a number =12x
2/3 of a number =10x
Given Differnce 2x=8
implies x=4. Answer = 60
4/5 Of a number exceeds it’s 2/3 by 8. The number is
Assume the original number be 15X
4/5 of a number =12x
2/3 of a number =10x
Given Differnce 2x=8
implies x=4. Answer = 60
Explanation for Question 2
if the given series is in arithmetic progression then average=(first-term + last-term)/2
The series is: 10,20,30.....190
The average is (10+ 190)/2
answer=100
if the given series is in arithmetic progression then average=(first-term + last-term)/2
The series is: 10,20,30.....190
The average is (10+ 190)/2
answer=100
Explanation for Question 3
Let x be the side of the cube then volume=x3
if side double i.e 2x the volume = (2x)3
given the volume x3 weighs 6 pounds
then 8x3weighs (8)(6)pounds
answer=48
Let x be the side of the cube then volume=x3
if side double i.e 2x the volume = (2x)3
given the volume x3 weighs 6 pounds
then 8x3weighs (8)(6)pounds
answer=48
Explanation for Question 4
the information given in the question is
(25%(600) = 15% n
25 x (600/15) = n
n = 1000
the information given in the question is
(25%(600) = 15% n
25 x (600/15) = n
n = 1000
Explanation for Question 5
sum of the terms of arithmetic progression is
(first term + last term)n/2,where 'n' is number of terms.
From the question
n=50 (all even numbers from 2 to 100)
first term=2
last term=100
substitute in the above formula: (2 + 100)50/2
ans= 2550
sum of the terms of arithmetic progression is
(first term + last term)n/2,where 'n' is number of terms.
From the question
n=50 (all even numbers from 2 to 100)
first term=2
last term=100
substitute in the above formula: (2 + 100)50/2
ans= 2550